The handle of a 22 kg lawnmower makes a 33-degree angle with the horizontal?
maddmatt316 asked:
The handle of a 22 kg lawnmower makes a 33-degree angle with the horizontal. If the coefficient of friction between lawnmower and ground is 0.62, what magnitude of force is required to push the mower at constant velocity? Assume the force is applied in the direction of the handle.
This entry was posted
on Monday, February 15th, 2010 at 12:00 am and is filed under Physics.
You can follow any responses to this entry through the RSS 2.0 feed.
You can leave a response, or trackback from your own site.
The handle of a 22 kg lawnmower makes a 33-degree angle with the horizontal. If the coefficient of friction between lawnmower and ground is 0.62, what magnitude of force is required to push the mower at constant velocity? Assume the force is applied in the direction of the handle.
February 16th, 2010 at 8:59 am
The horizontal force needed to keep the lawnmower moving is
22 * g * .62
The horizontal component, h, of a force, f, applied at a 33-degree angle is
h = f * cos(33) garyp