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	<title>Comments on: The handle of a 22 kg lawnmower makes a 33-degree angle with the horizontal?</title>
	<atom:link href="http://www.qualitylawnmower.com/blog/the-handle-of-a-22-kg-lawnmower-makes-a-33-degree-angle-with-the-horizontal/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.qualitylawnmower.com/blog/the-handle-of-a-22-kg-lawnmower-makes-a-33-degree-angle-with-the-horizontal/</link>
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	<pubDate>Thu, 17 May 2012 16:22:39 +0000</pubDate>
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		<title>By: garyp</title>
		<link>http://www.qualitylawnmower.com/blog/the-handle-of-a-22-kg-lawnmower-makes-a-33-degree-angle-with-the-horizontal/comment-page-1/#comment-2739</link>
		<dc:creator>garyp</dc:creator>
		<pubDate>Tue, 16 Feb 2010 13:59:27 +0000</pubDate>
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		<description>The horizontal force needed to keep the lawnmower moving is

22 * g * .62

The horizontal component, h, of a force, f, applied at a 33-degree angle is

h = f * cos(33)&lt;a href="http://www.greatjewelrydesign.com/other-320"&gt; garyp&lt;/a&gt;</description>
		<content:encoded><![CDATA[<p>The horizontal force needed to keep the lawnmower moving is</p>
<p>22 * g * .62</p>
<p>The horizontal component, h, of a force, f, applied at a 33-degree angle is</p>
<p>h = f * cos(33)<a href="http://www.greatjewelrydesign.com/other-320"> garyp</a></p>
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